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翻訳と辞書　辞書検索 [ 開発暫定版 ] スポンサード リンク truncated octahedron ： ウィキペディア英語版 truncated octahedron In geometry, the truncated octahedron is an Archimedean solid. It has 14 faces (8 regular hexagonal and 6 square), 36 edges, and 24 vertices. Since each of its faces has point symmetry the truncated octahedron is a zonohedron. It is also the Goldberg polyhedron GIV(1,1), containing square and hexagonal faces. Like the cube, it can tessellate (or "pack") 3-dimensional space, as a permutohedron. If the original truncated octahedron has unit edge length, its dual tetrakis cube has edge lengths $\backslash tfrac\backslash scriptstyle\; \backslash scriptstyle\{\backslash sqrt\{2\}\}$. ==Construction== A truncated octahedron is constructed from a regular octahedron with side length 3''a'' by the removal of six right square pyramids, one from each point. These pyramids have both base side length (''a'') and lateral side length (''e'') of ''a'', to form equilateral triangles. The base area is then ''a''2. Note that this shape is exactly similar to half an octahedron or Johnson solid J1. From the properties of square pyramids, we can now find the slant height, ''s'', and the height, ''h'', of the pyramid: ::$h\; =\; \backslash sqrta^2\}=\backslash fraca$ ::$s\; =\; \backslash sqrta^2\}\; =\; \backslash sqrta^2\; +\; \backslash fraca^2\}=\backslash fraca$ The volume, ''V'', of the pyramid is given by: ::$V\; =\; \backslash fraca^2h\; =\; \backslash fraca^3$ Because six pyramids are removed by truncation, there is a total lost volume of $\backslash scriptstyle$. 抄文引用元・出典: フリー百科事典『 ウィキペディア（Wikipedia）』 ■ウィキペディアで「truncated octahedron」の詳細全文を読む スポンサード リンク 翻訳と辞書 : 翻訳のためのインターネットリソース Copyright(C) kotoba.ne.jp 1997-2016. All Rights Reserved.